313424013403 has 4 divisors (see below), whose sum is σ = 313728014448. Its totient is φ = 313120012360.

The previous prime is 313424013317. The next prime is 313424013449. The reversal of 313424013403 is 304310424313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-313424013403 is a prime.

It is a super-2 number, since 2×313424013403² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (313424013503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151998976 + ... + 152001037.

It is an arithmetic number, because the mean of its divisors is an integer number (78432003612).

Almost surely, 2^313424013403 is an apocalyptic number.

313424013403 is a deficient number, since it is larger than the sum of its proper divisors (304001045).

313424013403 is a wasteful number, since it uses less digits than its factorization.

313424013403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 304001044.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 313424013403 its reverse (304310424313), we get a palindrome (617734437716).

The spelling of 313424013403 in words is "three hundred thirteen billion, four hundred twenty-four million, thirteen thousand, four hundred three".