Base | Representation |
---|---|
bin | 101101100111000010110… |
… | …101110001010100001001 |
3 | 102002122011202110220020001 |
4 | 231213002311301110021 |
5 | 402323021302044223 |
6 | 10355513315203001 |
7 | 442305606466450 |
oct | 55470265612411 |
9 | 12078152426201 |
10 | 3134300034313 |
11 | aa9281727278 |
12 | 4275468a6461 |
13 | 199742536726 |
14 | ab9b54d7b97 |
15 | 567e4d469ad |
hex | 2d9c2d71509 |
3134300034313 has 4 divisors (see below), whose sum is σ = 3582057182080. Its totient is φ = 2686542886548.
The previous prime is 3134300034311. The next prime is 3134300034373.
3134300034313 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3134300034313 - 21 = 3134300034311 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3134300034311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223878573873 + ... + 223878573886.
It is an arithmetic number, because the mean of its divisors is an integer number (895514295520).
Almost surely, 23134300034313 is an apocalyptic number.
It is an amenable number.
3134300034313 is a deficient number, since it is larger than the sum of its proper divisors (447757147767).
3134300034313 is an equidigital number, since it uses as much as digits as its factorization.
3134300034313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 447757147766.
The product of its (nonzero) digits is 11664, while the sum is 28.
It can be divided in two parts, 31343000 and 34313, that added together give a palindrome (31377313).
The spelling of 3134300034313 in words is "three trillion, one hundred thirty-four billion, three hundred million, thirty-four thousand, three hundred thirteen".
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