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31344012313 = 47666893879
BaseRepresentation
bin11101001100001111…
…111010110000011001
32222220102021210122221
4131030033322300121
51003143031343223
622222122544041
72156506465045
oct351417726031
988812253587
1031344012313
1112324972409
1260a9068021
132c5696cc63
141734b45025
15c36b0eb5d
hex74c3fac19

31344012313 has 4 divisors (see below), whose sum is σ = 32010906240. Its totient is φ = 30677118388.

The previous prime is 31344012299. The next prime is 31344012341. The reversal of 31344012313 is 31321044313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31344012313 - 25 = 31344012281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31344012383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333446893 + ... + 333446986.

It is an arithmetic number, because the mean of its divisors is an integer number (8002726560).

Almost surely, 231344012313 is an apocalyptic number.

It is an amenable number.

31344012313 is a deficient number, since it is larger than the sum of its proper divisors (666893927).

31344012313 is an equidigital number, since it uses as much as digits as its factorization.

31344012313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 666893926.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 31344012313 its reverse (31321044313), we get a palindrome (62665056626).

The spelling of 31344012313 in words is "thirty-one billion, three hundred forty-four million, twelve thousand, three hundred thirteen".

Divisors: 1 47 666893879 31344012313