Base | Representation |
---|---|
bin | 101101100111001010011… |
… | …111000010110010100011 |
3 | 102002122111200211011212012 |
4 | 231213022133002302203 |
5 | 402323302120404212 |
6 | 10355534140223135 |
7 | 442312024622342 |
oct | 55471237026243 |
9 | 12078450734765 |
10 | 3134428294307 |
11 | aa933806a972 |
12 | 42758183aaab |
13 | 199762c9320b |
14 | ab9c8563b59 |
15 | 5680122e922 |
hex | 2d9ca7c2ca3 |
3134428294307 has 2 divisors, whose sum is σ = 3134428294308. Its totient is φ = 3134428294306.
The previous prime is 3134428294301. The next prime is 3134428294321. The reversal of 3134428294307 is 7034928244313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3134428294307 - 212 = 3134428290211 is a prime.
It is a super-2 number, since 2×31344282943072 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3134428294301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567214147153 + 1567214147154.
It is an arithmetic number, because the mean of its divisors is an integer number (1567214147154).
Almost surely, 23134428294307 is an apocalyptic number.
3134428294307 is a deficient number, since it is larger than the sum of its proper divisors (1).
3134428294307 is an equidigital number, since it uses as much as digits as its factorization.
3134428294307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3483648, while the sum is 50.
The spelling of 3134428294307 in words is "three trillion, one hundred thirty-four billion, four hundred twenty-eight million, two hundred ninety-four thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •