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3134440928481 = 35319713464959
BaseRepresentation
bin101101100111001011001…
…111001111010011100001
3102002122112120121001200120
4231213023033033103201
5402323313334202411
610355535311110453
7442312240202562
oct55471317172341
912078476531616
103134440928481
11aa934420a135
12427585b12429
13199765797a65
14ab9ca0d2169
15568023c8106
hex2d9cb3cf4e1

3134440928481 has 8 divisors (see below), whose sum is σ = 4258108431360. Its totient is φ = 2050200355632.

The previous prime is 3134440928473. The next prime is 3134440928503. The reversal of 3134440928481 is 1848290444313.

3134440928481 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 3134440928481 - 23 = 3134440928473 is a prime.

It is a super-2 number, since 2×31344409284812 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (3134440921481) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9856732321 + ... + 9856732638.

It is an arithmetic number, because the mean of its divisors is an integer number (532263553920).

Almost surely, 23134440928481 is an apocalyptic number.

It is an amenable number.

3134440928481 is a deficient number, since it is larger than the sum of its proper divisors (1123667502879).

3134440928481 is a wasteful number, since it uses less digits than its factorization.

3134440928481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19713465015.

The product of its (nonzero) digits is 2654208, while the sum is 51.

The spelling of 3134440928481 in words is "three trillion, one hundred thirty-four billion, four hundred forty million, nine hundred twenty-eight thousand, four hundred eighty-one".

Divisors: 1 3 53 159 19713464959 59140394877 1044813642827 3134440928481