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3134452544313 = 31044817514771
BaseRepresentation
bin101101100111001011111…
…011100011001100111001
3102002122120101110012121120
4231213023323203030321
5402323324322404223
610355540404055453
7442312441012146
oct55471373431471
912078511405546
103134452544313
11aa934a8232a2
12427589994589
13199768003c2c
14ab9cb8773cd
155680341ebe3
hex2d9cbee3339

3134452544313 has 4 divisors (see below), whose sum is σ = 4179270059088. Its totient is φ = 2089635029540.

The previous prime is 3134452544233. The next prime is 3134452544339.

3134452544313 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3134452544313 - 210 = 3134452543289 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3134452544383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 522408757383 + ... + 522408757388.

It is an arithmetic number, because the mean of its divisors is an integer number (1044817514772).

Almost surely, 23134452544313 is an apocalyptic number.

It is an amenable number.

3134452544313 is a deficient number, since it is larger than the sum of its proper divisors (1044817514775).

3134452544313 is a wasteful number, since it uses less digits than its factorization.

3134452544313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1044817514774.

The product of its digits is 1036800, while the sum is 42.

The spelling of 3134452544313 in words is "three trillion, one hundred thirty-four billion, four hundred fifty-two million, five hundred forty-four thousand, three hundred thirteen".

Divisors: 1 3 1044817514771 3134452544313