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31345054313 = 59531272107
BaseRepresentation
bin11101001100010011…
…111001001001101001
32222220111020202000112
4131030103321021221
51003143313214223
622222201144105
72156521364666
oct351423711151
988814222015
1031345054313
1112325514271
1260a948b035
132c56c46321
141734d36a6d
15c36c68778
hex74c4f9269

31345054313 has 4 divisors (see below), whose sum is σ = 31876326480. Its totient is φ = 30813782148.

The previous prime is 31345054309. The next prime is 31345054333.

31345054313 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31345054313 - 22 = 31345054309 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31345054313.

It is not an unprimeable number, because it can be changed into a prime (31345054333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265635995 + ... + 265636112.

It is an arithmetic number, because the mean of its divisors is an integer number (7969081620).

Almost surely, 231345054313 is an apocalyptic number.

It is an amenable number.

31345054313 is a deficient number, since it is larger than the sum of its proper divisors (531272167).

31345054313 is an equidigital number, since it uses as much as digits as its factorization.

31345054313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 531272166.

The product of its (nonzero) digits is 32400, while the sum is 32.

It can be divided in two parts, 313450 and 54313, that added together give a palindrome (367763).

The spelling of 31345054313 in words is "thirty-one billion, three hundred forty-five million, fifty-four thousand, three hundred thirteen".

Divisors: 1 59 531272107 31345054313