Base | Representation |
---|---|
bin | 101101100111101101111… |
… | …100001010110000001001 |
3 | 102002201001011010001022011 |
4 | 231213231330022300021 |
5 | 402331011410203112 |
6 | 10400113145455521 |
7 | 442332536640124 |
oct | 55475574126011 |
9 | 12081034101264 |
10 | 3135023131657 |
11 | aa9612911a8a |
12 | 427708aa15a1 |
13 | 1998292a1c91 |
14 | aba435653bb |
15 | 5683857caa7 |
hex | 2d9edf0ac09 |
3135023131657 has 2 divisors, whose sum is σ = 3135023131658. Its totient is φ = 3135023131656.
The previous prime is 3135023131637. The next prime is 3135023131699. The reversal of 3135023131657 is 7561313205313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3133622201616 + 1400930041 = 1770204^2 + 37429^2 .
It is a cyclic number.
It is not a de Polignac number, because 3135023131657 - 219 = 3135022607369 is a prime.
It is not a weakly prime, because it can be changed into another prime (3135023131637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567511565828 + 1567511565829.
It is an arithmetic number, because the mean of its divisors is an integer number (1567511565829).
Almost surely, 23135023131657 is an apocalyptic number.
It is an amenable number.
3135023131657 is a deficient number, since it is larger than the sum of its proper divisors (1).
3135023131657 is an equidigital number, since it uses as much as digits as its factorization.
3135023131657 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 170100, while the sum is 40.
The spelling of 3135023131657 in words is "three trillion, one hundred thirty-five billion, twenty-three million, one hundred thirty-one thousand, six hundred fifty-seven".
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