Base | Representation |
---|---|
bin | 101101101000000111000… |
… | …011011101110110110001 |
3 | 102002202010111221112010202 |
4 | 231220013003131312301 |
5 | 402332342241202223 |
6 | 10400223040404545 |
7 | 442346144205233 |
oct | 55500703356661 |
9 | 12082114845122 |
10 | 3135444475313 |
11 | aa9809735787 |
12 | 427806016755 |
13 | 199895677457 |
14 | aba834c4253 |
15 | 5686055a428 |
hex | 2da070dddb1 |
3135444475313 has 2 divisors, whose sum is σ = 3135444475314. Its totient is φ = 3135444475312.
The previous prime is 3135444475277. The next prime is 3135444475333. The reversal of 3135444475313 is 3135744445313.
3135444475313 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2903455826209 + 231988649104 = 1703953^2 + 481652^2 .
It is a cyclic number.
It is not a de Polignac number, because 3135444475313 - 26 = 3135444475249 is a prime.
It is not a weakly prime, because it can be changed into another prime (3135444475333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567722237656 + 1567722237657.
It is an arithmetic number, because the mean of its divisors is an integer number (1567722237657).
Almost surely, 23135444475313 is an apocalyptic number.
It is an amenable number.
3135444475313 is a deficient number, since it is larger than the sum of its proper divisors (1).
3135444475313 is an equidigital number, since it uses as much as digits as its factorization.
3135444475313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3628800, while the sum is 47.
The spelling of 3135444475313 in words is "three trillion, one hundred thirty-five billion, four hundred forty-four million, four hundred seventy-five thousand, three hundred thirteen".
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