Base | Representation |
---|---|
bin | 1110010001110110111110… |
… | …00010111100101000000001 |
3 | 11010011210202201022000010001 |
4 | 13020323133002330220001 |
5 | 13103424100433304122 |
6 | 150440534515040001 |
7 | 6420400051642405 |
oct | 710733702745001 |
9 | 133153681260101 |
10 | 31399953025537 |
11 | a006710984778 |
12 | 36316308a0001 |
13 | 146a0063a9b85 |
14 | 7a7aa1649105 |
15 | 396bb8c5a527 |
hex | 1c8edf0bca01 |
31399953025537 has 2 divisors, whose sum is σ = 31399953025538. Its totient is φ = 31399953025536.
The previous prime is 31399953025523. The next prime is 31399953025577. The reversal of 31399953025537 is 73552035999313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 27231949043776 + 4168003981761 = 5218424^2 + 2041569^2 .
It is a cyclic number.
It is not a de Polignac number, because 31399953025537 - 215 = 31399952992769 is a prime.
It is not a weakly prime, because it can be changed into another prime (31399953025577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15699976512768 + 15699976512769.
It is an arithmetic number, because the mean of its divisors is an integer number (15699976512769).
Almost surely, 231399953025537 is an apocalyptic number.
It is an amenable number.
31399953025537 is a deficient number, since it is larger than the sum of its proper divisors (1).
31399953025537 is an equidigital number, since it uses as much as digits as its factorization.
31399953025537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103335750, while the sum is 64.
The spelling of 31399953025537 in words is "thirty-one trillion, three hundred ninety-nine billion, nine hundred fifty-three million, twenty-five thousand, five hundred thirty-seven".
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