314001462001 has 2 divisors, whose sum is σ = 314001462002. Its totient is φ = 314001462000.

The previous prime is 314001461993. The next prime is 314001462007. The reversal of 314001462001 is 100264100413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 310470725601 + 3530736400 = 557199^2 + 59420^2 .

It is an emirp because it is prime and its reverse (100264100413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314001462001 - 2³ = 314001461993 is a prime.

It is a super-3 number, since 3×314001462001³ (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (314001462007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157000731000 + 157000731001.

It is an arithmetic number, because the mean of its divisors is an integer number (157000731001).

Almost surely, 2^314001462001 is an apocalyptic number.

It is an amenable number.

314001462001 is a deficient number, since it is larger than the sum of its proper divisors (1).

314001462001 is an equidigital number, since it uses as much as digits as its factorization.

314001462001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 314001462001 its reverse (100264100413), we get a palindrome (414265562414).

The spelling of 314001462001 in words is "three hundred fourteen billion, one million, four hundred sixty-two thousand, one".