Base | Representation |
---|---|
bin | 1110010001110111011101… |
… | …00000011011011111111011 |
3 | 11010011211102210101020000022 |
4 | 13020323232200123133323 |
5 | 13103430113334144121 |
6 | 150441020342401055 |
7 | 6420406351461353 |
oct | 710735640333773 |
9 | 133154383336008 |
10 | 31400212412411 |
11 | a006834339997 |
12 | 36316a373018b |
13 | 146a04805802b |
14 | 7a7ac7c89b63 |
15 | 396bd18e5aab |
hex | 1c8eee81b7fb |
31400212412411 has 2 divisors, whose sum is σ = 31400212412412. Its totient is φ = 31400212412410.
The previous prime is 31400212412383. The next prime is 31400212412417. The reversal of 31400212412411 is 11421421200413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31400212412411 - 26 = 31400212412347 is a prime.
It is a super-3 number, since 3×314002124124113 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (31400212412417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700106206205 + 15700106206206.
It is an arithmetic number, because the mean of its divisors is an integer number (15700106206206).
Almost surely, 231400212412411 is an apocalyptic number.
31400212412411 is a deficient number, since it is larger than the sum of its proper divisors (1).
31400212412411 is an equidigital number, since it uses as much as digits as its factorization.
31400212412411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 31400212412411 its reverse (11421421200413), we get a palindrome (42821633612824).
The spelling of 31400212412411 in words is "thirty-one trillion, four hundred billion, two hundred twelve million, four hundred twelve thousand, four hundred eleven".
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