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31401121320241 is a prime number
BaseRepresentation
bin1110010001111001001001…
…01011101000110100110001
311010011220210010122112011021
413020330210223220310301
513103433444024221431
6150441250451415441
76420441026200411
oct710744453506461
9133156703575137
1031401121320241
11a0071603a5892
1236318b7bb4581
13146a16145010a
147a7b72884641
15396c365d1b11
hex1c8f24ae8d31

31401121320241 has 2 divisors, whose sum is σ = 31401121320242. Its totient is φ = 31401121320240.

The previous prime is 31401121320161. The next prime is 31401121320253. The reversal of 31401121320241 is 14202312110413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24046312919616 + 7354808400625 = 4903704^2 + 2711975^2 .

It is a cyclic number.

It is not a de Polignac number, because 31401121320241 - 225 = 31401087765809 is a prime.

It is not a weakly prime, because it can be changed into another prime (31401121320271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700560660120 + 15700560660121.

It is an arithmetic number, because the mean of its divisors is an integer number (15700560660121).

Almost surely, 231401121320241 is an apocalyptic number.

It is an amenable number.

31401121320241 is a deficient number, since it is larger than the sum of its proper divisors (1).

31401121320241 is an equidigital number, since it uses as much as digits as its factorization.

31401121320241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 31401121320241 its reverse (14202312110413), we get a palindrome (45603433430654).

The spelling of 31401121320241 in words is "thirty-one trillion, four hundred one billion, one hundred twenty-one million, three hundred twenty thousand, two hundred forty-one".