Base | Representation |
---|---|
bin | 1110010001111001001001… |
… | …01011101000110100110001 |
3 | 11010011220210010122112011021 |
4 | 13020330210223220310301 |
5 | 13103433444024221431 |
6 | 150441250451415441 |
7 | 6420441026200411 |
oct | 710744453506461 |
9 | 133156703575137 |
10 | 31401121320241 |
11 | a0071603a5892 |
12 | 36318b7bb4581 |
13 | 146a16145010a |
14 | 7a7b72884641 |
15 | 396c365d1b11 |
hex | 1c8f24ae8d31 |
31401121320241 has 2 divisors, whose sum is σ = 31401121320242. Its totient is φ = 31401121320240.
The previous prime is 31401121320161. The next prime is 31401121320253. The reversal of 31401121320241 is 14202312110413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24046312919616 + 7354808400625 = 4903704^2 + 2711975^2 .
It is a cyclic number.
It is not a de Polignac number, because 31401121320241 - 225 = 31401087765809 is a prime.
It is not a weakly prime, because it can be changed into another prime (31401121320271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700560660120 + 15700560660121.
It is an arithmetic number, because the mean of its divisors is an integer number (15700560660121).
Almost surely, 231401121320241 is an apocalyptic number.
It is an amenable number.
31401121320241 is a deficient number, since it is larger than the sum of its proper divisors (1).
31401121320241 is an equidigital number, since it uses as much as digits as its factorization.
31401121320241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 31401121320241 its reverse (14202312110413), we get a palindrome (45603433430654).
The spelling of 31401121320241 in words is "thirty-one trillion, four hundred one billion, one hundred twenty-one million, three hundred twenty thousand, two hundred forty-one".
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