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314013412041122 = 2157006706020561
BaseRepresentation
bin100011101100101111111000…
…1111000010010000110100010
31112011211101111120222211020102
41013121133301320102012202
5312124243431440303442
63031503434153542402
7123066502036460303
oct10731376170220642
91464741446884212
10314013412041122
119106638186a112
122b275aa0414a02
131062a450bc6971
14577848a24a7aa
152648321e50232
hex11d97f1e121a2

314013412041122 has 4 divisors (see below), whose sum is σ = 471020118061686. Its totient is φ = 157006706020560.

The previous prime is 314013412041089. The next prime is 314013412041139. The reversal of 314013412041122 is 221140214310413.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 296982182715241 + 17031229325881 = 17233171^2 + 4126891^2 .

It is a super-3 number, since 3×3140134120411223 (a number of 44 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78503353010279 + ... + 78503353010282.

Almost surely, 2314013412041122 is an apocalyptic number.

314013412041122 is a deficient number, since it is larger than the sum of its proper divisors (157006706020564).

314013412041122 is a wasteful number, since it uses less digits than its factorization.

314013412041122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 157006706020563.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 314013412041122 its reverse (221140214310413), we get a palindrome (535153626351535).

The spelling of 314013412041122 in words is "three hundred fourteen trillion, thirteen billion, four hundred twelve million, forty-one thousand, one hundred twenty-two".

Divisors: 1 2 157006706020561 314013412041122