Base | Representation |
---|---|
bin | 100011101100101111111000… |
… | …1111000010010000110100010 |
3 | 1112011211101111120222211020102 |
4 | 1013121133301320102012202 |
5 | 312124243431440303442 |
6 | 3031503434153542402 |
7 | 123066502036460303 |
oct | 10731376170220642 |
9 | 1464741446884212 |
10 | 314013412041122 |
11 | 9106638186a112 |
12 | 2b275aa0414a02 |
13 | 1062a450bc6971 |
14 | 577848a24a7aa |
15 | 2648321e50232 |
hex | 11d97f1e121a2 |
314013412041122 has 4 divisors (see below), whose sum is σ = 471020118061686. Its totient is φ = 157006706020560.
The previous prime is 314013412041089. The next prime is 314013412041139. The reversal of 314013412041122 is 221140214310413.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 296982182715241 + 17031229325881 = 17233171^2 + 4126891^2 .
It is a super-3 number, since 3×3140134120411223 (a number of 44 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78503353010279 + ... + 78503353010282.
Almost surely, 2314013412041122 is an apocalyptic number.
314013412041122 is a deficient number, since it is larger than the sum of its proper divisors (157006706020564).
314013412041122 is a wasteful number, since it uses less digits than its factorization.
314013412041122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157006706020563.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 314013412041122 its reverse (221140214310413), we get a palindrome (535153626351535).
The spelling of 314013412041122 in words is "three hundred fourteen trillion, thirteen billion, four hundred twelve million, forty-one thousand, one hundred twenty-two".
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