Base | Representation |
---|---|
bin | 100011101100110100010110… |
… | …1011100111010001110101010 |
3 | 1112011212022020220010101220122 |
4 | 1013121220231130322032222 |
5 | 312124423101331324002 |
6 | 3031512101511523242 |
7 | 123100261500116111 |
oct | 10731505534721652 |
9 | 1464768226111818 |
10 | 314023001433002 |
11 | 9106a452823174 |
12 | 2b277917989522 |
13 | 1062b31b7ca244 |
14 | 5778b19a46c78 |
15 | 26486d3c516a2 |
hex | 11d9a2d73a3aa |
314023001433002 has 8 divisors (see below), whose sum is σ = 471035004442212. Its totient is φ = 157011333285600.
The previous prime is 314023001432999. The next prime is 314023001433013. The reversal of 314023001433002 is 200334100320413.
It can be written as a sum of positive squares in 2 ways, for example, as 291696988981321 + 22326012451681 = 17079139^2 + 4725041^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×3140230014330022 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81357749 + ... + 85130072.
Almost surely, 2314023001433002 is an apocalyptic number.
314023001433002 is a deficient number, since it is larger than the sum of its proper divisors (157012003009210).
314023001433002 is a wasteful number, since it uses less digits than its factorization.
314023001433002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 167430904.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 314023001433002 its reverse (200334100320413), we get a palindrome (514357101753415).
The spelling of 314023001433002 in words is "three hundred fourteen trillion, twenty-three billion, one million, four hundred thirty-three thousand, two".
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