Base | Representation |
---|---|
bin | 101101101101011000001… |
… | …110010010110100010001 |
3 | 102010021201202010201021022 |
4 | 231231120032102310101 |
5 | 402430433404013343 |
6 | 10403000232405225 |
7 | 442636262653325 |
oct | 55553016226421 |
9 | 12107652121238 |
10 | 3141101235473 |
11 | 1001151839383 |
12 | 428924546815 |
13 | 19a2875b6006 |
14 | ac05c8a5985 |
15 | 56a91e92568 |
hex | 2db58392d11 |
3141101235473 has 2 divisors, whose sum is σ = 3141101235474. Its totient is φ = 3141101235472.
The previous prime is 3141101235457. The next prime is 3141101235499. The reversal of 3141101235473 is 3745321011413.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2974479710224 + 166621525249 = 1724668^2 + 408193^2 .
It is an emirp because it is prime and its reverse (3745321011413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3141101235473 - 24 = 3141101235457 is a prime.
It is not a weakly prime, because it can be changed into another prime (3141101235073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570550617736 + 1570550617737.
It is an arithmetic number, because the mean of its divisors is an integer number (1570550617737).
Almost surely, 23141101235473 is an apocalyptic number.
It is an amenable number.
3141101235473 is a deficient number, since it is larger than the sum of its proper divisors (1).
3141101235473 is an equidigital number, since it uses as much as digits as its factorization.
3141101235473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 35.
Adding to 3141101235473 its reverse (3745321011413), we get a palindrome (6886422246886).
The spelling of 3141101235473 in words is "three trillion, one hundred forty-one billion, one hundred one million, two hundred thirty-five thousand, four hundred seventy-three".
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