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3141301213132 = 22785325303283
BaseRepresentation
bin101101101101100100001…
…001001001011111001100
3102010022020200102122001021
4231231210021021133030
5402431341102310012
610403032134523524
7442644241515505
oct55554411113714
912108220378037
103141301213132
111001244706575
1242897b5065a4
1319a2b9b630a4
14ac07b27dbac
1556aa47e5007
hex2db642497cc

3141301213132 has 6 divisors (see below), whose sum is σ = 5497277122988. Its totient is φ = 1570650606564.

The previous prime is 3141301213097. The next prime is 3141301213153. The reversal of 3141301213132 is 2313121031413.

3141301213132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 3141301213097 and 3141301213106.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 392662651638 + ... + 392662651645.

Almost surely, 23141301213132 is an apocalyptic number.

It is an amenable number.

3141301213132 is a deficient number, since it is larger than the sum of its proper divisors (2355975909856).

3141301213132 is a wasteful number, since it uses less digits than its factorization.

3141301213132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 785325303287 (or 785325303285 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 3141301213132 its reverse (2313121031413), we get a palindrome (5454422244545).

The spelling of 3141301213132 in words is "three trillion, one hundred forty-one billion, three hundred one million, two hundred thirteen thousand, one hundred thirty-two".

Divisors: 1 2 4 785325303283 1570650606566 3141301213132