Base | Representation |
---|---|
bin | 101101101110001110100… |
… | …101111011011111100001 |
3 | 102010101002022112112012211 |
4 | 231232032211323133201 |
5 | 402434320412313212 |
6 | 10403230535322121 |
7 | 443001010151236 |
oct | 55561645733741 |
9 | 12111068475184 |
10 | 3142013401057 |
11 | 100157a71a933 |
12 | 428b39b20341 |
13 | 19a3a157bb6b |
14 | ac107aab78d |
15 | 56ae70c39a7 |
hex | 2db8e97b7e1 |
3142013401057 has 2 divisors, whose sum is σ = 3142013401058. Its totient is φ = 3142013401056.
The previous prime is 3142013401013. The next prime is 3142013401067. The reversal of 3142013401057 is 7501043102413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2591485016481 + 550528384576 = 1609809^2 + 741976^2 .
It is a cyclic number.
It is not a de Polignac number, because 3142013401057 - 215 = 3142013368289 is a prime.
It is not a weakly prime, because it can be changed into another prime (3142013401067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571006700528 + 1571006700529.
It is an arithmetic number, because the mean of its divisors is an integer number (1571006700529).
Almost surely, 23142013401057 is an apocalyptic number.
It is an amenable number.
3142013401057 is a deficient number, since it is larger than the sum of its proper divisors (1).
3142013401057 is an equidigital number, since it uses as much as digits as its factorization.
3142013401057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
The spelling of 3142013401057 in words is "three trillion, one hundred forty-two billion, thirteen million, four hundred one thousand, fifty-seven".
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