Base | Representation |
---|---|
bin | 1110010010011100111011… |
… | …01110100110111110001001 |
3 | 11010020202100221221202020021 |
4 | 13021032131232212332021 |
5 | 13104242314443331101 |
6 | 150454145023300441 |
7 | 6422021055316354 |
oct | 711163556467611 |
9 | 133222327852207 |
10 | 31420332011401 |
11 | a014319326453 |
12 | 363557974a721 |
13 | 146bc034491a8 |
14 | 7a8a75dc529b |
15 | 3974acdd85a1 |
hex | 1c939dba6f89 |
31420332011401 has 2 divisors, whose sum is σ = 31420332011402. Its totient is φ = 31420332011400.
The previous prime is 31420332011363. The next prime is 31420332011407. The reversal of 31420332011401 is 10411023302413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23973518668176 + 7446813343225 = 4896276^2 + 2728885^2 .
It is an emirp because it is prime and its reverse (10411023302413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31420332011401 - 213 = 31420332003209 is a prime.
It is not a weakly prime, because it can be changed into another prime (31420332011407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15710166005700 + 15710166005701.
It is an arithmetic number, because the mean of its divisors is an integer number (15710166005701).
Almost surely, 231420332011401 is an apocalyptic number.
It is an amenable number.
31420332011401 is a deficient number, since it is larger than the sum of its proper divisors (1).
31420332011401 is an equidigital number, since it uses as much as digits as its factorization.
31420332011401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 31420332011401 its reverse (10411023302413), we get a palindrome (41831355313814).
The spelling of 31420332011401 in words is "thirty-one trillion, four hundred twenty billion, three hundred thirty-two million, eleven thousand, four hundred one".
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