Base | Representation |
---|---|
bin | 101101101110010011111… |
… | …000101011001101110001 |
3 | 102010101022111122001010001 |
4 | 231232103320223031301 |
5 | 402440011130414301 |
6 | 10403243430510001 |
7 | 443003136015625 |
oct | 55562370531561 |
9 | 12111274561101 |
10 | 3142102201201 |
11 | 1001615861787 |
12 | 428b63805301 |
13 | 19a3b6aa0922 |
14 | ac1157c5185 |
15 | 56aeecb4c01 |
hex | 2db93e2b371 |
3142102201201 has 4 divisors (see below), whose sum is σ = 3144285734400. Its totient is φ = 3139918668004.
The previous prime is 3142102201187. The next prime is 3142102201207. The reversal of 3142102201201 is 1021022012413.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3142102201201 - 25 = 3142102201169 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3142102201207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1091764441 + ... + 1091767318.
It is an arithmetic number, because the mean of its divisors is an integer number (786071433600).
Almost surely, 23142102201201 is an apocalyptic number.
It is an amenable number.
3142102201201 is a deficient number, since it is larger than the sum of its proper divisors (2183533199).
3142102201201 is a wasteful number, since it uses less digits than its factorization.
3142102201201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2183533198.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 3142102201201 its reverse (1021022012413), we get a palindrome (4163124213614).
The spelling of 3142102201201 in words is "three trillion, one hundred forty-two billion, one hundred two million, two hundred one thousand, two hundred one".
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