Base | Representation |
---|---|
bin | 101101101110011011000… |
… | …011010001110100000011 |
3 | 102010101121212211212000111 |
4 | 231232123003101310003 |
5 | 402440232414440001 |
6 | 10403303403332151 |
7 | 443006125614454 |
oct | 55563303216403 |
9 | 12111555755014 |
10 | 3142222421251 |
11 | 10016777038a1 |
12 | 428b97b21057 |
13 | 19a405973a54 |
14 | ac12775b12b |
15 | 56b0a610851 |
hex | 2db9b0d1d03 |
3142222421251 has 2 divisors, whose sum is σ = 3142222421252. Its totient is φ = 3142222421250.
The previous prime is 3142222421183. The next prime is 3142222421287. The reversal of 3142222421251 is 1521242222413.
3142222421251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3142222421251 - 215 = 3142222388483 is a prime.
It is a super-3 number, since 3×31422224212513 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (3142222461251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571111210625 + 1571111210626.
It is an arithmetic number, because the mean of its divisors is an integer number (1571111210626).
Almost surely, 23142222421251 is an apocalyptic number.
3142222421251 is a deficient number, since it is larger than the sum of its proper divisors (1).
3142222421251 is an equidigital number, since it uses as much as digits as its factorization.
3142222421251 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15360, while the sum is 31.
Adding to 3142222421251 its reverse (1521242222413), we get a palindrome (4663464643664).
The spelling of 3142222421251 in words is "three trillion, one hundred forty-two billion, two hundred twenty-two million, four hundred twenty-one thousand, two hundred fifty-one".
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