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314223140401 = 595325815939
BaseRepresentation
bin1001001001010010010…
…10001001111000110001
31010001001202021102101221
410210221022021320301
520122012110443101
6400204020225041
731462512424102
oct4445112117061
91101052242357
10314223140401
11111296853195
1250a9483b181
1323828737711
14112cc1023a9
1582911bcaa1
hex4929289e31

314223140401 has 4 divisors (see below), whose sum is σ = 319548956400. Its totient is φ = 308897324404.

The previous prime is 314223140369. The next prime is 314223140419. The reversal of 314223140401 is 104041322413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 314223140401 - 25 = 314223140369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314223140501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2662907911 + ... + 2662908028.

It is an arithmetic number, because the mean of its divisors is an integer number (79887239100).

Almost surely, 2314223140401 is an apocalyptic number.

It is an amenable number.

314223140401 is a deficient number, since it is larger than the sum of its proper divisors (5325815999).

314223140401 is an equidigital number, since it uses as much as digits as its factorization.

314223140401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5325815998.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 314223140401 its reverse (104041322413), we get a palindrome (418264462814).

The spelling of 314223140401 in words is "three hundred fourteen billion, two hundred twenty-three million, one hundred forty thousand, four hundred one".

Divisors: 1 59 5325815939 314223140401