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3143044102481 is a prime number
BaseRepresentation
bin101101101111001100000…
…001101111100101010001
3102010110202010222120202122
4231233030001233211101
5402443423242234411
610403521115024025
7443035364031533
oct55571401574521
912113663876678
103143044102481
111001a59503098
1242918713b015
1319a506c7836a
14ac1a492b853
1556b5781b9db
hex2dbcc06f951

3143044102481 has 2 divisors, whose sum is σ = 3143044102482. Its totient is φ = 3143044102480.

The previous prime is 3143044102477. The next prime is 3143044102511. The reversal of 3143044102481 is 1842014403413.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2813952570256 + 329091532225 = 1677484^2 + 573665^2 .

It is a cyclic number.

It is not a de Polignac number, because 3143044102481 - 22 = 3143044102477 is a prime.

It is a super-2 number, since 2×31430441024812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3143044102441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571522051240 + 1571522051241.

It is an arithmetic number, because the mean of its divisors is an integer number (1571522051241).

Almost surely, 23143044102481 is an apocalyptic number.

It is an amenable number.

3143044102481 is a deficient number, since it is larger than the sum of its proper divisors (1).

3143044102481 is an equidigital number, since it uses as much as digits as its factorization.

3143044102481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36864, while the sum is 35.

Adding to 3143044102481 its reverse (1842014403413), we get a palindrome (4985058505894).

The spelling of 3143044102481 in words is "three trillion, one hundred forty-three billion, forty-four million, one hundred two thousand, four hundred eighty-one".