Base | Representation |
---|---|
bin | 1110010010110100111001… |
… | …10001111111110011110011 |
3 | 11010021222120211021100002112 |
4 | 13021122130301333303303 |
5 | 13110000143430233433 |
6 | 150504114015035535 |
7 | 6422655011162264 |
oct | 711323461776363 |
9 | 133258524240075 |
10 | 31433201024243 |
11 | a019822575257 |
12 | 3637b6b50bbab |
13 | 14701a4647ca5 |
14 | 7a95371b496b |
15 | 3979b2ab4348 |
hex | 1c969cc7fcf3 |
31433201024243 has 2 divisors, whose sum is σ = 31433201024244. Its totient is φ = 31433201024242.
The previous prime is 31433201024207. The next prime is 31433201024249. The reversal of 31433201024243 is 34242010233413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31433201024243 - 26 = 31433201024179 is a prime.
It is a super-2 number, since 2×314332010242432 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31433201024249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15716600512121 + 15716600512122.
It is an arithmetic number, because the mean of its divisors is an integer number (15716600512122).
Almost surely, 231433201024243 is an apocalyptic number.
31433201024243 is a deficient number, since it is larger than the sum of its proper divisors (1).
31433201024243 is an equidigital number, since it uses as much as digits as its factorization.
31433201024243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 31433201024243 its reverse (34242010233413), we get a palindrome (65675211257656).
The spelling of 31433201024243 in words is "thirty-one trillion, four hundred thirty-three billion, two hundred one million, twenty-four thousand, two hundred forty-three".
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