Base | Representation |
---|---|
bin | 1110010010110111000000… |
… | …10001010100110001011001 |
3 | 11010022002111201212102012120 |
4 | 13021123200101110301121 |
5 | 13110010003311410131 |
6 | 150504422223531453 |
7 | 6423025040354124 |
oct | 711334021246131 |
9 | 133262451772176 |
10 | 31434333310041 |
11 | a01a253731342 |
12 | 3638226759b89 |
13 | 14703250c119c |
14 | 7a96037193bb |
15 | 397a2c1c6496 |
hex | 1c96e0454c59 |
31434333310041 has 8 divisors (see below), whose sum is σ = 42486587487840. Its totient is φ = 20669150669472.
The previous prime is 31434333310033. The next prime is 31434333310067. The reversal of 31434333310041 is 14001333343413.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31434333310041 - 23 = 31434333310033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31434333309984 and 31434333310011.
It is not an unprimeable number, because it can be changed into a prime (31434333310031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71767884051 + ... + 71767884488.
It is an arithmetic number, because the mean of its divisors is an integer number (5310823435980).
Almost surely, 231434333310041 is an apocalyptic number.
It is an amenable number.
31434333310041 is a deficient number, since it is larger than the sum of its proper divisors (11052254177799).
31434333310041 is a wasteful number, since it uses less digits than its factorization.
31434333310041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143535768615.
The product of its (nonzero) digits is 46656, while the sum is 33.
Adding to 31434333310041 its reverse (14001333343413), we get a palindrome (45435666653454).
The spelling of 31434333310041 in words is "thirty-one trillion, four hundred thirty-four billion, three hundred thirty-three million, three hundred ten thousand, forty-one".
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