Base | Representation |
---|---|
bin | 1110010011000010010111… |
… | …01110101001010010001011 |
3 | 11010022200020200222112122212 |
4 | 13021201023232221102023 |
5 | 13110110000332010033 |
6 | 150511311253135335 |
7 | 6423332123056151 |
oct | 711411356512213 |
9 | 133280220875585 |
10 | 31440431125643 |
11 | a0218a27a1471 |
12 | 363944892a54b |
13 | 1470a875173b7 |
14 | 7a9a2150b3d1 |
15 | 397c876d1748 |
hex | 1c984bba948b |
31440431125643 has 2 divisors, whose sum is σ = 31440431125644. Its totient is φ = 31440431125642.
The previous prime is 31440431125619. The next prime is 31440431125661. The reversal of 31440431125643 is 34652113404413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31440431125643 - 216 = 31440431060107 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31440431125643.
It is not a weakly prime, because it can be changed into another prime (31440431125603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15720215562821 + 15720215562822.
It is an arithmetic number, because the mean of its divisors is an integer number (15720215562822).
Almost surely, 231440431125643 is an apocalyptic number.
31440431125643 is a deficient number, since it is larger than the sum of its proper divisors (1).
31440431125643 is an equidigital number, since it uses as much as digits as its factorization.
31440431125643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 41.
The spelling of 31440431125643 in words is "thirty-one trillion, four hundred forty billion, four hundred thirty-one million, one hundred twenty-five thousand, six hundred forty-three".
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