Base | Representation |
---|---|
bin | 1110010011000011110100… |
… | …01010010110110110110011 |
3 | 11010022202020222211200101101 |
4 | 13021201322022112312303 |
5 | 13110113044244022011 |
6 | 150511520442145231 |
7 | 6423360332436226 |
oct | 711417212266663 |
9 | 133282228750341 |
10 | 31441210142131 |
11 | a022162500049 |
12 | 36396257b2217 |
13 | 1470b7ca312ba |
14 | 7a9a96b735bd |
15 | 397cd0cb12c1 |
hex | 1c987a296db3 |
31441210142131 has 2 divisors, whose sum is σ = 31441210142132. Its totient is φ = 31441210142130.
The previous prime is 31441210142081. The next prime is 31441210142149. The reversal of 31441210142131 is 13124101214413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31441210142131 - 27 = 31441210142003 is a prime.
It is a super-2 number, since 2×314412101421312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 31441210142131.
It is not a weakly prime, because it can be changed into another prime (31441250142131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15720605071065 + 15720605071066.
It is an arithmetic number, because the mean of its divisors is an integer number (15720605071066).
Almost surely, 231441210142131 is an apocalyptic number.
31441210142131 is a deficient number, since it is larger than the sum of its proper divisors (1).
31441210142131 is an equidigital number, since it uses as much as digits as its factorization.
31441210142131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 31441210142131 its reverse (13124101214413), we get a palindrome (44565311356544).
The spelling of 31441210142131 in words is "thirty-one trillion, four hundred forty-one billion, two hundred ten million, one hundred forty-two thousand, one hundred thirty-one".
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