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314435050313 is a prime number
BaseRepresentation
bin1001001001101011100…
…10100001101101001001
31010001121112000120011012
410210311302201231021
520122430333102223
6400241030213305
731500664554206
oct4446562415511
91101545016135
10314435050313
1111139543024a
1250b337b4235
13238606019b7
141130c304cad
1582a4acac78
hex4935ca1b49

314435050313 has 2 divisors, whose sum is σ = 314435050314. Its totient is φ = 314435050312.

The previous prime is 314435050283. The next prime is 314435050339. The reversal of 314435050313 is 313050534413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 258055872064 + 56379178249 = 507992^2 + 237443^2 .

It is an emirp because it is prime and its reverse (313050534413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314435050313 - 220 = 314434001737 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 314435050313.

It is not a weakly prime, because it can be changed into another prime (314435050343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157217525156 + 157217525157.

It is an arithmetic number, because the mean of its divisors is an integer number (157217525157).

Almost surely, 2314435050313 is an apocalyptic number.

It is an amenable number.

314435050313 is a deficient number, since it is larger than the sum of its proper divisors (1).

314435050313 is an equidigital number, since it uses as much as digits as its factorization.

314435050313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 32.

Adding to 314435050313 its reverse (313050534413), we get a palindrome (627485584726).

The spelling of 314435050313 in words is "three hundred fourteen billion, four hundred thirty-five million, fifty thousand, three hundred thirteen".