Base | Representation |
---|---|
bin | 1110010011001010111000… |
… | …00011101110010110000011 |
3 | 11010100010001010020011022002 |
4 | 13021211130003232112003 |
5 | 13110143330003213042 |
6 | 150513344505134215 |
7 | 6423553262241341 |
oct | 711453403562603 |
9 | 133303033204262 |
10 | 31445000054147 |
11 | a023827841039 |
12 | 363a302a8a36b |
13 | 1471334c75aa4 |
14 | 7a9d3623a991 |
15 | 397e53888132 |
hex | 1c995c0ee583 |
31445000054147 has 2 divisors, whose sum is σ = 31445000054148. Its totient is φ = 31445000054146.
The previous prime is 31445000054141. The next prime is 31445000054263. The reversal of 31445000054147 is 74145000054413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31445000054147 - 210 = 31445000053123 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31445000054147.
It is not a weakly prime, because it can be changed into another prime (31445000054141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15722500027073 + 15722500027074.
It is an arithmetic number, because the mean of its divisors is an integer number (15722500027074).
Almost surely, 231445000054147 is an apocalyptic number.
31445000054147 is a deficient number, since it is larger than the sum of its proper divisors (1).
31445000054147 is an equidigital number, since it uses as much as digits as its factorization.
31445000054147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 134400, while the sum is 38.
The spelling of 31445000054147 in words is "thirty-one trillion, four hundred forty-five billion, fifty-four thousand, one hundred forty-seven".
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