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31450021433 = 139226259147
BaseRepresentation
bin11101010010100100…
…010011111000111001
310000011210202121211122
4131102210103320321
51003402201141213
622240431035025
72162234525405
oct352244237071
9100153677748
1031450021433
1112379798656
12611866ba75
132c7290894c
141744c5c105
15c4109ed08
hex752913e39

31450021433 has 4 divisors (see below), whose sum is σ = 31676280720. Its totient is φ = 31223762148.

The previous prime is 31450021417. The next prime is 31450021439. The reversal of 31450021433 is 33412005413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31450021433 - 24 = 31450021417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31450021439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113129435 + ... + 113129712.

It is an arithmetic number, because the mean of its divisors is an integer number (7919070180).

Almost surely, 231450021433 is an apocalyptic number.

It is an amenable number.

31450021433 is a deficient number, since it is larger than the sum of its proper divisors (226259287).

31450021433 is a wasteful number, since it uses less digits than its factorization.

31450021433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 226259286.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 31450021433 its reverse (33412005413), we get a palindrome (64862026846).

The spelling of 31450021433 in words is "thirty-one billion, four hundred fifty million, twenty-one thousand, four hundred thirty-three".

Divisors: 1 139 226259147 31450021433