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3145757314433 is a prime number
BaseRepresentation
bin101101110001101101101…
…111110100110110000001
3102010201202020101000212012
4231301231233310312001
5403020002333030213
610405050240342305
7443162540662466
oct55615557646601
912121666330765
103145757314433
111003120aa3418
12429803914995
1319a84a109616
14ac380ddd66d
1556c65b114a8
hex2dc6dbf4d81

3145757314433 has 2 divisors, whose sum is σ = 3145757314434. Its totient is φ = 3145757314432.

The previous prime is 3145757314331. The next prime is 3145757314463. The reversal of 3145757314433 is 3344137575413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2172758544784 + 972998769649 = 1474028^2 + 986407^2 .

It is a cyclic number.

It is not a de Polignac number, because 3145757314433 - 28 = 3145757314177 is a prime.

It is a super-3 number, since 3×31457573144333 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (3145757314463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572878657216 + 1572878657217.

It is an arithmetic number, because the mean of its divisors is an integer number (1572878657217).

Almost surely, 23145757314433 is an apocalyptic number.

It is an amenable number.

3145757314433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3145757314433 is an equidigital number, since it uses as much as digits as its factorization.

3145757314433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6350400, while the sum is 50.

The spelling of 3145757314433 in words is "three trillion, one hundred forty-five billion, seven hundred fifty-seven million, three hundred fourteen thousand, four hundred thirty-three".