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314948439907 = 376963835489
BaseRepresentation
bin1001001010101000110…
…00111100111101100011
31010002221022001110021121
410211110120330331203
520130003300034112
6400404010033111
731516500365653
oct4452430747543
91102838043247
10314948439907
11111629202472
1251057718797
1323912a9441a
141135a584363
1582d4bdb407
hex495463cf63

314948439907 has 4 divisors (see below), whose sum is σ = 314949652360. Its totient is φ = 314947227456.

The previous prime is 314948439877. The next prime is 314948439941. The reversal of 314948439907 is 709934849413.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-314948439907 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314948439607) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40782 + ... + 794707.

It is an arithmetic number, because the mean of its divisors is an integer number (78737413090).

Almost surely, 2314948439907 is an apocalyptic number.

314948439907 is a deficient number, since it is larger than the sum of its proper divisors (1212453).

314948439907 is an equidigital number, since it uses as much as digits as its factorization.

314948439907 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1212452.

The product of its (nonzero) digits is 23514624, while the sum is 61.

The spelling of 314948439907 in words is "three hundred fourteen billion, nine hundred forty-eight million, four hundred thirty-nine thousand, nine hundred seven".

Divisors: 1 376963 835489 314948439907