Base | Representation |
---|---|
bin | 1110010100101000001110… |
… | …01110100000110101111001 |
3 | 11010111220101211000122221102 |
4 | 13022110013032200311321 |
5 | 13112003444301122432 |
6 | 150552353505021145 |
7 | 6430306226336414 |
oct | 712240716406571 |
9 | 133456354018842 |
10 | 31495116426617 |
11 | a043005168488 |
12 | 3647b6a9247b5 |
13 | 1475c90b6c55c |
14 | 7ac52c1c0b7b |
15 | 3993d8568962 |
hex | 1ca5073a0d79 |
31495116426617 has 2 divisors, whose sum is σ = 31495116426618. Its totient is φ = 31495116426616.
The previous prime is 31495116426589. The next prime is 31495116426629. The reversal of 31495116426617 is 71662461159413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31495116426601 + 16 = 5612051^2 + 4^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31495116426617 is a prime.
It is not a weakly prime, because it can be changed into another prime (31495116426517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15747558213308 + 15747558213309.
It is an arithmetic number, because the mean of its divisors is an integer number (15747558213309).
Almost surely, 231495116426617 is an apocalyptic number.
It is an amenable number.
31495116426617 is a deficient number, since it is larger than the sum of its proper divisors (1).
31495116426617 is an equidigital number, since it uses as much as digits as its factorization.
31495116426617 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6531840, while the sum is 56.
The spelling of 31495116426617 in words is "thirty-one trillion, four hundred ninety-five billion, one hundred sixteen million, four hundred twenty-six thousand, six hundred seventeen".
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