315006052350113 has 2 divisors, whose sum is σ = 315006052350114. Its totient is φ = 315006052350112.

The previous prime is 315006052350029. The next prime is 315006052350131. The reversal of 315006052350113 is 311053250600513.

Together with next prime (315006052350131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 211694846769169 + 103311205580944 = 14549737^2 + 10164212^2 .

It is a cyclic number.

It is not a de Polignac number, because 315006052350113 - 2¹² = 315006052346017 is a prime.

It is a super-2 number, since 2×315006052350113² (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (315006052350193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157503026175056 + 157503026175057.

It is an arithmetic number, because the mean of its divisors is an integer number (157503026175057).

Almost surely, 2^{315006052350113} is an apocalyptic number.

It is an amenable number.

315006052350113 is a deficient number, since it is larger than the sum of its proper divisors (1).

315006052350113 is an equidigital number, since it uses as much as digits as its factorization.

315006052350113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40500, while the sum is 35.

The spelling of 315006052350113 in words is "three hundred fifteen trillion, six billion, fifty-two million, three hundred fifty thousand, one hundred thirteen".