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315006231661081 is a prime number
BaseRepresentation
bin100011110011111110001101…
…0100010100100101000011001
31112022100022010220021011000221
41013213330122202210220121
5312242030230301123311
63033543510504000041
7123231310035136612
oct10747743242445031
91468308126234027
10315006231661081
1191409435639224
122b3b6399760021
131069cc636b16cc
1457b0550bc0c09
15266407d11b671
hex11e7f1a8a4a19

315006231661081 has 2 divisors, whose sum is σ = 315006231661082. Its totient is φ = 315006231661080.

The previous prime is 315006231661063. The next prime is 315006231661097. The reversal of 315006231661081 is 180166132600513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 302154608934025 + 12851622727056 = 17382595^2 + 3584916^2 .

It is a cyclic number.

It is not a de Polignac number, because 315006231661081 - 239 = 314456475847193 is a prime.

It is a super-2 number, since 2×3150062316610812 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (315006231961081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157503115830540 + 157503115830541.

It is an arithmetic number, because the mean of its divisors is an integer number (157503115830541).

Almost surely, 2315006231661081 is an apocalyptic number.

It is an amenable number.

315006231661081 is a deficient number, since it is larger than the sum of its proper divisors (1).

315006231661081 is an equidigital number, since it uses as much as digits as its factorization.

315006231661081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 43.

The spelling of 315006231661081 in words is "three hundred fifteen trillion, six billion, two hundred thirty-one million, six hundred sixty-one thousand, eighty-one".