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315031542113 is a prime number
BaseRepresentation
bin1001001010110010101…
…01111101100101100001
31010010011002102111002002
410211121111331211201
520130141033321423
6400420135133345
731521526632311
oct4453125754541
91103132374062
10315031542113
11111671102382
125107b514255
132392706c822
1411367617441
1582dc154228
hex495957d961

315031542113 has 2 divisors, whose sum is σ = 315031542114. Its totient is φ = 315031542112.

The previous prime is 315031542103. The next prime is 315031542127. The reversal of 315031542113 is 311245130513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 309300597904 + 5730944209 = 556148^2 + 75703^2 .

It is a cyclic number.

It is not a de Polignac number, because 315031542113 - 214 = 315031525729 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (315031542103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157515771056 + 157515771057.

It is an arithmetic number, because the mean of its divisors is an integer number (157515771057).

Almost surely, 2315031542113 is an apocalyptic number.

It is an amenable number.

315031542113 is a deficient number, since it is larger than the sum of its proper divisors (1).

315031542113 is an equidigital number, since it uses as much as digits as its factorization.

315031542113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 315031542113 its reverse (311245130513), we get a palindrome (626276672626).

The spelling of 315031542113 in words is "three hundred fifteen billion, thirty-one million, five hundred forty-two thousand, one hundred thirteen".