Base | Representation |
---|---|
bin | 1001001010110100111… |
… | …01001110011101000011 |
3 | 1010010012101120121000121 |
4 | 10211122131032131003 |
5 | 20130210324122202 |
6 | 400422043401111 |
7 | 31522144466632 |
oct | 4453235163503 |
9 | 1103171517017 |
10 | 315050223427 |
11 | 111680701985 |
12 | 51085823197 |
13 | 2392abb0964 |
14 | 11369cbb519 |
15 | 82ddae4537 |
hex | 495a74e743 |
315050223427 has 2 divisors, whose sum is σ = 315050223428. Its totient is φ = 315050223426.
The previous prime is 315050223419. The next prime is 315050223529. The reversal of 315050223427 is 724322050513.
It is a weak prime.
It is an emirp because it is prime and its reverse (724322050513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 315050223427 - 23 = 315050223419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 315050223392 and 315050223401.
It is not a weakly prime, because it can be changed into another prime (315050223407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157525111713 + 157525111714.
It is an arithmetic number, because the mean of its divisors is an integer number (157525111714).
Almost surely, 2315050223427 is an apocalyptic number.
315050223427 is a deficient number, since it is larger than the sum of its proper divisors (1).
315050223427 is an equidigital number, since it uses as much as digits as its factorization.
315050223427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 34.
The spelling of 315050223427 in words is "three hundred fifteen billion, fifty million, two hundred twenty-three thousand, four hundred twenty-seven".
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