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315104209457 is a prime number
BaseRepresentation
bin1001001010111011010…
…11001010101000110001
31010010100011011100221012
410211131223022220301
520130313134200312
6400431252440305
731523401405412
oct4453553125061
91103304140835
10315104209457
111116a9125434
125109b919095
132393913345b
1411373131809
1582e370a322
hex495dacaa31

315104209457 has 2 divisors, whose sum is σ = 315104209458. Its totient is φ = 315104209456.

The previous prime is 315104209439. The next prime is 315104209499. The reversal of 315104209457 is 754902401513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 303927279616 + 11176929841 = 551296^2 + 105721^2 .

It is a cyclic number.

It is not a de Polignac number, because 315104209457 - 220 = 315103160881 is a prime.

It is not a weakly prime, because it can be changed into another prime (315104109457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157552104728 + 157552104729.

It is an arithmetic number, because the mean of its divisors is an integer number (157552104729).

Almost surely, 2315104209457 is an apocalyptic number.

It is an amenable number.

315104209457 is a deficient number, since it is larger than the sum of its proper divisors (1).

315104209457 is an equidigital number, since it uses as much as digits as its factorization.

315104209457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 41.

The spelling of 315104209457 in words is "three hundred fifteen billion, one hundred four million, two hundred nine thousand, four hundred fifty-seven".