Base | Representation |
---|---|
bin | 11101010110001011… |
… | …001101111000111001 |
3 | 10000100000122220022222 |
4 | 131112023031320321 |
5 | 1004013200131441 |
6 | 22250432253425 |
7 | 2163601162616 |
oct | 352613157071 |
9 | 100300586288 |
10 | 31510552121 |
11 | 123aa981214 |
12 | 61349a1275 |
13 | 2c82310319 |
14 | 174ccd750d |
15 | c46559d4b |
hex | 7562cde39 |
31510552121 has 2 divisors, whose sum is σ = 31510552122. Its totient is φ = 31510552120.
The previous prime is 31510552063. The next prime is 31510552153. The reversal of 31510552121 is 12125501513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18513412096 + 12997140025 = 136064^2 + 114005^2 .
It is an emirp because it is prime and its reverse (12125501513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31510552121 - 210 = 31510551097 is a prime.
It is not a weakly prime, because it can be changed into another prime (31510552921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15755276060 + 15755276061.
It is an arithmetic number, because the mean of its divisors is an integer number (15755276061).
Almost surely, 231510552121 is an apocalyptic number.
It is an amenable number.
31510552121 is a deficient number, since it is larger than the sum of its proper divisors (1).
31510552121 is an equidigital number, since it uses as much as digits as its factorization.
31510552121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1500, while the sum is 26.
The spelling of 31510552121 in words is "thirty-one billion, five hundred ten million, five hundred fifty-two thousand, one hundred twenty-one".
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