Base | Representation |
---|---|
bin | 100011110100101100111101… |
… | …0011110011011000111000100 |
3 | 1112022200220021111212020020202 |
4 | 1013221121322132123013010 |
5 | 312300201332102342202 |
6 | 3034101552454550032 |
7 | 123241462633133354 |
oct | 10751317236330704 |
9 | 1468626244766222 |
10 | 315106625434052 |
11 | 91447a73276831 |
12 | 2b411937368318 |
13 | 106a95729622ba |
14 | 57b5356264b64 |
15 | 26669a6bd9802 |
hex | 11e967a79b1c4 |
315106625434052 has 12 divisors (see below), whose sum is σ = 552018892926480. Its totient is φ = 157386941740776.
The previous prime is 315106625434031. The next prime is 315106625434109. The reversal of 315106625434052 is 250434526601513.
It is a super-2 number, since 2×3151066254340522 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 315106625433988 and 315106625434006.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41592739802 + ... + 41592747377.
It is an arithmetic number, because the mean of its divisors is an integer number (46001574410540).
Almost surely, 2315106625434052 is an apocalyptic number.
It is an amenable number.
315106625434052 is a deficient number, since it is larger than the sum of its proper divisors (236912267492428).
315106625434052 is a wasteful number, since it uses less digits than its factorization.
315106625434052 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83185488130 (or 83185488128 counting only the distinct ones).
The product of its (nonzero) digits is 2592000, while the sum is 47.
The spelling of 315106625434052 in words is "three hundred fifteen trillion, one hundred six billion, six hundred twenty-five million, four hundred thirty-four thousand, fifty-two".
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