Base | Representation |
---|---|
bin | 11101010110001110… |
… | …011101001100011011 |
3 | 10000100002021001002221 |
4 | 131112032131030123 |
5 | 1004013404314433 |
6 | 22250502404511 |
7 | 2163611330320 |
oct | 352616351433 |
9 | 100302231087 |
10 | 31511401243 |
11 | 12400401173 |
12 | 6135130737 |
13 | 2c8254996a |
14 | 174d078b47 |
15 | c4667672d |
hex | 75639d31b |
31511401243 has 8 divisors (see below), whose sum is σ = 36052742912. Its totient is φ = 26979987816.
The previous prime is 31511401231. The next prime is 31511401253. The reversal of 31511401243 is 34210411513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31511401243 - 29 = 31511400731 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31511401253) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2475255 + ... + 2487952.
It is an arithmetic number, because the mean of its divisors is an integer number (4506592864).
Almost surely, 231511401243 is an apocalyptic number.
31511401243 is a deficient number, since it is larger than the sum of its proper divisors (4541341669).
31511401243 is an equidigital number, since it uses as much as digits as its factorization.
31511401243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4964121.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 31511401243 its reverse (34210411513), we get a palindrome (65721812756).
The spelling of 31511401243 in words is "thirty-one billion, five hundred eleven million, four hundred one thousand, two hundred forty-three".
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