Base | Representation |
---|---|
bin | 1001001010111111000… |
… | …01001010110011011011 |
3 | 1010010102022100221221211 |
4 | 10211133201022303123 |
5 | 20130344044040011 |
6 | 400434315443551 |
7 | 31524225343144 |
oct | 4453741126333 |
9 | 1103368327854 |
10 | 315135143131 |
11 | 111714633356 |
12 | 510aa1565b7 |
13 | 239426743c3 |
14 | 113772a4acb |
15 | 82e62bab21 |
hex | 495f84acdb |
315135143131 has 2 divisors, whose sum is σ = 315135143132. Its totient is φ = 315135143130.
The previous prime is 315135143119. The next prime is 315135143203. The reversal of 315135143131 is 131341531513.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 315135143131 - 233 = 306545208539 is a prime.
It is a super-2 number, since 2×3151351431312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 315135143093 and 315135143102.
It is not a weakly prime, because it can be changed into another prime (315135143111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157567571565 + 157567571566.
It is an arithmetic number, because the mean of its divisors is an integer number (157567571566).
Almost surely, 2315135143131 is an apocalyptic number.
315135143131 is a deficient number, since it is larger than the sum of its proper divisors (1).
315135143131 is an equidigital number, since it uses as much as digits as its factorization.
315135143131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8100, while the sum is 31.
Adding to 315135143131 its reverse (131341531513), we get a palindrome (446476674644).
The spelling of 315135143131 in words is "three hundred fifteen billion, one hundred thirty-five million, one hundred forty-three thousand, one hundred thirty-one".
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