Base | Representation |
---|---|
bin | 100011110100111010011011… |
… | …0110100100000100111010111 |
3 | 1112022210122221200012202220011 |
4 | 1013221310312310200213113 |
5 | 312301140104104103101 |
6 | 3034123135255021051 |
7 | 123243535555456450 |
oct | 10751646664404727 |
9 | 1468718850182804 |
10 | 315135555144151 |
11 | 91459269348155 |
12 | 2b41746b96a787 |
13 | 106ac203379761 |
14 | 57b68dc4a6127 |
15 | 26675eb89a751 |
hex | 11e9d36d209d7 |
315135555144151 has 16 divisors (see below), whose sum is σ = 360192129111360. Its totient is φ = 270088285098240.
The previous prime is 315135555144143. The next prime is 315135555144161. The reversal of 315135555144151 is 151441555531513.
It is not a de Polignac number, because 315135555144151 - 23 = 315135555144143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 315135555144095 and 315135555144104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (315135555144161) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3236459395 + ... + 3236556763.
It is an arithmetic number, because the mean of its divisors is an integer number (22512008069460).
Almost surely, 2315135555144151 is an apocalyptic number.
315135555144151 is a deficient number, since it is larger than the sum of its proper divisors (45056573967209).
315135555144151 is a wasteful number, since it uses less digits than its factorization.
315135555144151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140394.
The product of its digits is 2250000, while the sum is 49.
The spelling of 315135555144151 in words is "three hundred fifteen trillion, one hundred thirty-five billion, five hundred fifty-five million, one hundred forty-four thousand, one hundred fifty-one".
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