31514024041 has 2 divisors, whose sum is σ = 31514024042. Its totient is φ = 31514024040.

The previous prime is 31514024029. The next prime is 31514024081. The reversal of 31514024041 is 14042041513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25824490000 + 5689534041 = 160700^2 + 75429^2 .

It is an emirp because it is prime and its reverse (14042041513) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31514024041 - 2⁷ = 31514023913 is a prime.

It is a super-2 number, since 2×31514024041² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31514023997 and 31514024015.

It is not a weakly prime, because it can be changed into another prime (31514024081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15757012020 + 15757012021.

It is an arithmetic number, because the mean of its divisors is an integer number (15757012021).

Almost surely, 2^31514024041 is an apocalyptic number.

It is an amenable number.

31514024041 is a deficient number, since it is larger than the sum of its proper divisors (1).

31514024041 is an equidigital number, since it uses as much as digits as its factorization.

31514024041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 31514024041 its reverse (14042041513), we get a palindrome (45556065554).

The spelling of 31514024041 in words is "thirty-one billion, five hundred fourteen million, twenty-four thousand, forty-one".