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315148600537 is a prime number
BaseRepresentation
bin1001001011000000101…
…00100000010011011001
31010010110020200200001021
410211200110200103121
520130411020204122
6400435520122441
731524450622441
oct4454024402331
91103406620037
10315148600537
11111721195081
12510b2766421
13239453a6874
1411378da9121
1582e75781c7
hex49605204d9

315148600537 has 2 divisors, whose sum is σ = 315148600538. Its totient is φ = 315148600536.

The previous prime is 315148600519. The next prime is 315148600573. The reversal of 315148600537 is 735006841513.

Together with next prime (315148600573) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 315075651856 + 72948681 = 561316^2 + 8541^2 .

It is a cyclic number.

It is not a de Polignac number, because 315148600537 - 27 = 315148600409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 315148600493 and 315148600502.

It is not a weakly prime, because it can be changed into another prime (315148600577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157574300268 + 157574300269.

It is an arithmetic number, because the mean of its divisors is an integer number (157574300269).

Almost surely, 2315148600537 is an apocalyptic number.

It is an amenable number.

315148600537 is a deficient number, since it is larger than the sum of its proper divisors (1).

315148600537 is an equidigital number, since it uses as much as digits as its factorization.

315148600537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 43.

The spelling of 315148600537 in words is "three hundred fifteen billion, one hundred forty-eight million, six hundred thousand, five hundred thirty-seven".