Base | Representation |
---|---|
bin | 1001001011000110110… |
… | …01000011100100111011 |
3 | 1010010120211122101122201 |
4 | 10211203121003210323 |
5 | 20131012213001433 |
6 | 400445000331031 |
7 | 31525644600313 |
oct | 4454331034473 |
9 | 1103524571581 |
10 | 315200125243 |
11 | 111748287383 |
12 | 51107a73a77 |
13 | 23952c76c63 |
14 | 11381b7c443 |
15 | 82ebd54a7d |
hex | 496364393b |
315200125243 has 4 divisors (see below), whose sum is σ = 315724585288. Its totient is φ = 314675665200.
The previous prime is 315200125223. The next prime is 315200125259. The reversal of 315200125243 is 342521002513.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 315200125243 - 233 = 306610190651 is a prime.
It is a super-2 number, since 2×3152001252432 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (315200125223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 262229121 + ... + 262230322.
It is an arithmetic number, because the mean of its divisors is an integer number (78931146322).
Almost surely, 2315200125243 is an apocalyptic number.
315200125243 is a deficient number, since it is larger than the sum of its proper divisors (524460045).
315200125243 is an equidigital number, since it uses as much as digits as its factorization.
315200125243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 524460044.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 315200125243 its reverse (342521002513), we get a palindrome (657721127756).
The spelling of 315200125243 in words is "three hundred fifteen billion, two hundred million, one hundred twenty-five thousand, two hundred forty-three".
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