Base | Representation |
---|---|
bin | 11101010110110000… |
… | …100101111101100011 |
3 | 10000100201002200120021 |
4 | 131112300211331203 |
5 | 1004023202200201 |
6 | 22251422254311 |
7 | 2164050361201 |
oct | 352660457543 |
9 | 100321080507 |
10 | 31520350051 |
11 | 12405463583 |
12 | 6138127397 |
13 | 2c84360c08 |
14 | 1750328071 |
15 | c47342ea1 |
hex | 756c25f63 |
31520350051 has 8 divisors (see below), whose sum is σ = 31606189344. Its totient is φ = 31434627840.
The previous prime is 31520350049. The next prime is 31520350073. The reversal of 31520350051 is 15005302513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31520350051 - 21 = 31520350049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31520349998 and 31520350025.
It is not an unprimeable number, because it can be changed into a prime (31520350031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 524010 + ... + 581056.
It is an arithmetic number, because the mean of its divisors is an integer number (3950773668).
Almost surely, 231520350051 is an apocalyptic number.
31520350051 is a deficient number, since it is larger than the sum of its proper divisors (85839293).
31520350051 is an equidigital number, since it uses as much as digits as its factorization.
31520350051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58541.
The product of its (nonzero) digits is 2250, while the sum is 25.
Adding to 31520350051 its reverse (15005302513), we get a palindrome (46525652564).
The spelling of 31520350051 in words is "thirty-one billion, five hundred twenty million, three hundred fifty thousand, fifty-one".
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