Base | Representation |
---|---|
bin | 1001001011001000011… |
… | …11111110111101010001 |
3 | 1010010121211201221100221 |
4 | 10211210033332331101 |
5 | 20131024404233431 |
6 | 400450233113041 |
7 | 31526211151021 |
oct | 4454417767521 |
9 | 1103554657327 |
10 | 315214524241 |
11 | 111755421581 |
12 | 51110858781 |
13 | 23955c48b86 |
14 | 11383a49a81 |
15 | 82ed24b111 |
hex | 49643fef51 |
315214524241 has 2 divisors, whose sum is σ = 315214524242. Its totient is φ = 315214524240.
The previous prime is 315214524217. The next prime is 315214524283. The reversal of 315214524241 is 142425412513.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 288910550016 + 26303974225 = 537504^2 + 162185^2 .
It is an emirp because it is prime and its reverse (142425412513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 315214524241 - 211 = 315214522193 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 315214524197 and 315214524206.
It is not a weakly prime, because it can be changed into another prime (315214522241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157607262120 + 157607262121.
It is an arithmetic number, because the mean of its divisors is an integer number (157607262121).
Almost surely, 2315214524241 is an apocalyptic number.
It is an amenable number.
315214524241 is a deficient number, since it is larger than the sum of its proper divisors (1).
315214524241 is an equidigital number, since it uses as much as digits as its factorization.
315214524241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 38400, while the sum is 34.
Adding to 315214524241 its reverse (142425412513), we get a palindrome (457639936754).
The spelling of 315214524241 in words is "three hundred fifteen billion, two hundred fourteen million, five hundred twenty-four thousand, two hundred forty-one".
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