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3152422241233 is a prime number
BaseRepresentation
bin101101110111111011000…
…000100000001111010001
3102011100221201121101121221
4231313323000200033101
5403122130043204413
610412111445045041
7443516650634116
oct55677300401721
912140851541557
103152422241233
111005a31198591
1242ab639b6781
1319b36cb845a5
14ac81425690d
1557005cde68d
hex2ddfb0203d1

3152422241233 has 2 divisors, whose sum is σ = 3152422241234. Its totient is φ = 3152422241232.

The previous prime is 3152422241207. The next prime is 3152422241261. The reversal of 3152422241233 is 3321422242513.

3152422241233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2352520966849 + 799901274384 = 1533793^2 + 894372^2 .

It is a cyclic number.

It is not a de Polignac number, because 3152422241233 - 241 = 953398985681 is a prime.

It is not a weakly prime, because it can be changed into another prime (3152422241263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1576211120616 + 1576211120617.

It is an arithmetic number, because the mean of its divisors is an integer number (1576211120617).

Almost surely, 23152422241233 is an apocalyptic number.

It is an amenable number.

3152422241233 is a deficient number, since it is larger than the sum of its proper divisors (1).

3152422241233 is an equidigital number, since it uses as much as digits as its factorization.

3152422241233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 34.

Adding to 3152422241233 its reverse (3321422242513), we get a palindrome (6473844483746).

The spelling of 3152422241233 in words is "three trillion, one hundred fifty-two billion, four hundred twenty-two million, two hundred forty-one thousand, two hundred thirty-three".