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315300210051 = 3531983020189
BaseRepresentation
bin1001001011010010101…
…10110110010110000011
31010010211210222020012110
410211221112312112003
520131213323210201
6400502533430403
731531301364621
oct4455126662603
91103753866173
10315300210051
111117998265a2
125113549b403
132396a91a238
1411391192511
158305a246d6
hex49695b6583

315300210051 has 8 divisors (see below), whose sum is σ = 428332361040. Its totient is φ = 206234099552.

The previous prime is 315300209999. The next prime is 315300210053. The reversal of 315300210051 is 150012003513.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 315300210051 - 214 = 315300193667 is a prime.

It is not an unprimeable number, because it can be changed into a prime (315300210053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 991509936 + ... + 991510253.

It is an arithmetic number, because the mean of its divisors is an integer number (53541545130).

Almost surely, 2315300210051 is an apocalyptic number.

315300210051 is a deficient number, since it is larger than the sum of its proper divisors (113032150989).

315300210051 is a wasteful number, since it uses less digits than its factorization.

315300210051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1983020245.

The product of its (nonzero) digits is 450, while the sum is 21.

Adding to 315300210051 its reverse (150012003513), we get a palindrome (465312213564).

The spelling of 315300210051 in words is "three hundred fifteen billion, three hundred million, two hundred ten thousand, fifty-one".

Divisors: 1 3 53 159 1983020189 5949060567 105100070017 315300210051